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498308350093 is a prime number
BaseRepresentation
bin1110100000001010111…
…11100000000010001101
31202122012222001222211021
413100011133200002031
531131013414200333
61020530353154141
751000355042411
oct7200537400215
91678188058737
10498308350093
11182371088924
12806aa55b951
1337cb48360b8
141a1926b2d41
15ce6737d82d
hex74057e008d

498308350093 has 2 divisors, whose sum is σ = 498308350094. Its totient is φ = 498308350092.

The previous prime is 498308350039. The next prime is 498308350103. The reversal of 498308350093 is 390053803894.

Together with previous prime (498308350039) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 418249345284 + 80059004809 = 646722^2 + 282947^2 .

It is a cyclic number.

It is not a de Polignac number, because 498308350093 - 225 = 498274795661 is a prime.

It is a super-2 number, since 2×4983083500932 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 498308350093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (498308350003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249154175046 + 249154175047.

It is an arithmetic number, because the mean of its divisors is an integer number (249154175047).

Almost surely, 2498308350093 is an apocalyptic number.

It is an amenable number.

498308350093 is a deficient number, since it is larger than the sum of its proper divisors (1).

498308350093 is an equidigital number, since it uses as much as digits as its factorization.

498308350093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 52.

The spelling of 498308350093 in words is "four hundred ninety-eight billion, three hundred eight million, three hundred fifty thousand, ninety-three".