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499000000433 = 1145363636403
BaseRepresentation
bin1110100001011101011…
…01111011111110110001
31202201000011112110201112
413100232231323332301
531133423000003213
61021123141443105
751023454006614
oct7205655737661
91681004473645
10499000000433
11182696544a80
1280862110495
1338094c10b5c
141a21a4b617b
15cea7e51ea8
hex742eb7bfb1

499000000433 has 4 divisors (see below), whose sum is σ = 544363636848. Its totient is φ = 453636364020.

The previous prime is 499000000427. The next prime is 499000000459. The reversal of 499000000433 is 334000000994.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 499000000433 - 210 = 498999999409 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 499000000433.

It is not an unprimeable number, because it can be changed into a prime (499000000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22681818191 + ... + 22681818212.

It is an arithmetic number, because the mean of its divisors is an integer number (136090909212).

Almost surely, 2499000000433 is an apocalyptic number.

It is an amenable number.

499000000433 is a deficient number, since it is larger than the sum of its proper divisors (45363636415).

499000000433 is a wasteful number, since it uses less digits than its factorization.

499000000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45363636414.

The product of its (nonzero) digits is 11664, while the sum is 32.

The spelling of 499000000433 in words is "four hundred ninety-nine billion, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 11 45363636403 499000000433