Base | Representation |
---|---|
bin | 101110011111111010… |
… | …111100000100101101 |
3 | 11202212112201022210101 |
4 | 232133322330010231 |
5 | 1304222440334023 |
6 | 34534135111101 |
7 | 3415153114216 |
oct | 563772740455 |
9 | 152775638711 |
10 | 49927668013 |
11 | 1a1a0959a53 |
12 | 9814812491 |
13 | 4928a95932 |
14 | 25b8ca240d |
15 | 14733581ad |
hex | b9febc12d |
49927668013 has 2 divisors, whose sum is σ = 49927668014. Its totient is φ = 49927668012.
The previous prime is 49927667987. The next prime is 49927668113. The reversal of 49927668013 is 31086672994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48751315209 + 1176352804 = 220797^2 + 34298^2 .
It is a cyclic number.
It is not a de Polignac number, because 49927668013 - 29 = 49927667501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49927668113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24963834006 + 24963834007.
It is an arithmetic number, because the mean of its divisors is an integer number (24963834007).
Almost surely, 249927668013 is an apocalyptic number.
It is an amenable number.
49927668013 is a deficient number, since it is larger than the sum of its proper divisors (1).
49927668013 is an equidigital number, since it uses as much as digits as its factorization.
49927668013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3919104, while the sum is 55.
The spelling of 49927668013 in words is "forty-nine billion, nine hundred twenty-seven million, six hundred sixty-eight thousand, thirteen".
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