Base | Representation |
---|---|
bin | 100100010110001111110… |
… | …0100111011010101100011 |
3 | 122200120110022222012021001 |
4 | 1020230133210323111203 |
5 | 1123321420121123141 |
6 | 14342534122412431 |
7 | 1023630022444024 |
oct | 110543744732543 |
9 | 18616408865231 |
10 | 4995576739171 |
11 | 16566809201a7 |
12 | 688214661117 |
13 | 2a3108878875 |
14 | 133b04134c4b |
15 | 89e2e240a31 |
hex | 48b1f93b563 |
4995576739171 has 2 divisors, whose sum is σ = 4995576739172. Its totient is φ = 4995576739170.
The previous prime is 4995576739009. The next prime is 4995576739187. The reversal of 4995576739171 is 1719376755994.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4995576739171 - 215 = 4995576706403 is a prime.
It is a super-2 number, since 2×49955767391712 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4995576739094 and 4995576739103.
It is not a weakly prime, because it can be changed into another prime (4995576730171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2497788369585 + 2497788369586.
It is an arithmetic number, because the mean of its divisors is an integer number (2497788369586).
Almost surely, 24995576739171 is an apocalyptic number.
4995576739171 is a deficient number, since it is larger than the sum of its proper divisors (1).
4995576739171 is an equidigital number, since it uses as much as digits as its factorization.
4995576739171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 450084600, while the sum is 73.
The spelling of 4995576739171 in words is "four trillion, nine hundred ninety-five billion, five hundred seventy-six million, seven hundred thirty-nine thousand, one hundred seventy-one".
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