Base | Representation |
---|---|
bin | 1110100011010010011… |
… | …01011101111010010011 |
3 | 1202210112120002220120111 |
4 | 13101221031131322103 |
5 | 31142430211010103 |
6 | 1021404355222151 |
7 | 51060001210012 |
oct | 7215115357223 |
9 | 1683476086514 |
10 | 499981344403 |
11 | 18304a486252 |
12 | 80a968a7957 |
13 | 381c0318568 |
14 | 1a2b0968a79 |
15 | d01419a86d |
hex | 746935de93 |
499981344403 has 2 divisors, whose sum is σ = 499981344404. Its totient is φ = 499981344402.
The previous prime is 499981344397. The next prime is 499981344409. The reversal of 499981344403 is 304443189994.
It is a balanced prime because it is at equal distance from previous prime (499981344397) and next prime (499981344409).
It is a cyclic number.
It is not a de Polignac number, because 499981344403 - 229 = 499444473491 is a prime.
It is not a weakly prime, because it can be changed into another prime (499981344409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249990672201 + 249990672202.
It is an arithmetic number, because the mean of its divisors is an integer number (249990672202).
Almost surely, 2499981344403 is an apocalyptic number.
499981344403 is a deficient number, since it is larger than the sum of its proper divisors (1).
499981344403 is an equidigital number, since it uses as much as digits as its factorization.
499981344403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13436928, while the sum is 58.
The spelling of 499981344403 in words is "four hundred ninety-nine billion, nine hundred eighty-one million, three hundred forty-four thousand, four hundred three".
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