Base | Representation |
---|---|
bin | 1110100011010010011… |
… | …01011110101001001011 |
3 | 1202210112120010001200121 |
4 | 13101221031132221023 |
5 | 31142430211104103 |
6 | 1021404355244111 |
7 | 51060001221526 |
oct | 7215115365113 |
9 | 1683476101617 |
10 | 499981347403 |
11 | 18304a48852a |
12 | 80a968a9637 |
13 | 381c0319a35 |
14 | 1a2b0969bbd |
15 | d01419b6bd |
hex | 746935ea4b |
499981347403 has 2 divisors, whose sum is σ = 499981347404. Its totient is φ = 499981347402.
The previous prime is 499981347389. The next prime is 499981347427. The reversal of 499981347403 is 304743189994.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-499981347403 is a prime.
It is not a weakly prime, because it can be changed into another prime (499981344403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249990673701 + 249990673702.
It is an arithmetic number, because the mean of its divisors is an integer number (249990673702).
Almost surely, 2499981347403 is an apocalyptic number.
499981347403 is a deficient number, since it is larger than the sum of its proper divisors (1).
499981347403 is an equidigital number, since it uses as much as digits as its factorization.
499981347403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23514624, while the sum is 61.
The spelling of 499981347403 in words is "four hundred ninety-nine billion, nine hundred eighty-one million, three hundred forty-seven thousand, four hundred three".
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