Base | Representation |
---|---|
bin | 10110101111001100010010… |
… | …01000100000000111001011 |
3 | 20120000221210000101100021211 |
4 | 23113212021020200013023 |
5 | 23023200012320000021 |
6 | 254201404554513551 |
7 | 13350244661053666 |
oct | 1327461110400713 |
9 | 216027700340254 |
10 | 50000015000011 |
11 | 14a27983a7389a |
12 | 5736407a358b7 |
13 | 21b8c9a87561b |
14 | c4c0295d06dd |
15 | 5ba9361243e1 |
hex | 2d79892201cb |
50000015000011 has 2 divisors, whose sum is σ = 50000015000012. Its totient is φ = 50000015000010.
The previous prime is 50000014999981. The next prime is 50000015000021. The reversal of 50000015000011 is 11000051000005.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50000015000011 - 221 = 50000012902859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50000014999955 and 50000015000000.
It is not a weakly prime, because it can be changed into another prime (50000015000021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000007500005 + 25000007500006.
It is an arithmetic number, because the mean of its divisors is an integer number (25000007500006).
Almost surely, 250000015000011 is an apocalyptic number.
50000015000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
50000015000011 is an equidigital number, since it uses as much as digits as its factorization.
50000015000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25, while the sum is 13.
Adding to 50000015000011 its reverse (11000051000005), we get a palindrome (61000066000016).
The spelling of 50000015000011 in words is "fifty trillion, fifteen million, eleven", and thus it is an aban number and an uban number.
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