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50000111341 = 437871477501
BaseRepresentation
bin101110100100001111…
…010010011011101101
311210001121000211100121
4232210033102123231
51304400012030331
634545243524541
73420022635235
oct564417223355
9153047024317
1050000111341
111a228839774
129834b29751
13493aaab5cb
1425c475ccc5
1514798b7c11
hexba43d26ed

50000111341 has 8 divisors (see below), whose sum is σ = 51227949344. Its totient is φ = 48775230000.

The previous prime is 50000111321. The next prime is 50000111347. The reversal of 50000111341 is 14311100005.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50000111341 - 29 = 50000110829 is a prime.

It is a super-2 number, since 2×500001113412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50000111347) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 704910 + ... + 772591.

It is an arithmetic number, because the mean of its divisors is an integer number (6403493668).

Almost surely, 250000111341 is an apocalyptic number.

It is an amenable number.

50000111341 is a deficient number, since it is larger than the sum of its proper divisors (1227838003).

50000111341 is a wasteful number, since it uses less digits than its factorization.

50000111341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1478331.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 50000111341 its reverse (14311100005), we get a palindrome (64311211346).

The spelling of 50000111341 in words is "fifty billion, one hundred eleven thousand, three hundred forty-one".

Divisors: 1 43 787 33841 1477501 63532543 1162793287 50000111341