5000025113 has 2 divisors, whose sum is σ = 5000025114. Its totient is φ = 5000025112.

The previous prime is 5000025097. The next prime is 5000025127. The reversal of 5000025113 is 3115200005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3161587984 + 1838437129 = 56228^2 + 42877^2 .

It is a cyclic number.

It is not a de Polignac number, because 5000025113 - 2⁴ = 5000025097 is a prime.

It is a super-2 number, since 2×5000025113² = 50000502261261325538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5000025091 and 5000025100.

It is not a weakly prime, because it can be changed into another prime (5000025133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2500012556 + 2500012557.

It is an arithmetic number, because the mean of its divisors is an integer number (2500012557).

Almost surely, 2^5000025113 is an apocalyptic number.

It is an amenable number.

5000025113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5000025113 is an equidigital number, since it uses as much as digits as its factorization.

5000025113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 5000025113 is about 70710.8556941577. The cubic root of 5000025113 is about 1709.9788095136.

Adding to 5000025113 its reverse (3115200005), we get a palindrome (8115225118).

The spelling of 5000025113 in words is "five billion, twenty-five thousand, one hundred thirteen".