Base | Representation |
---|---|
bin | 101110100100010000… |
… | …101110110111100001 |
3 | 11210001121202001201021 |
4 | 232210100232313201 |
5 | 1304400111134303 |
6 | 34545300005441 |
7 | 3420026103121 |
oct | 564420566741 |
9 | 153047661637 |
10 | 50000489953 |
11 | 1a228a78177 |
12 | 9835090881 |
13 | 493abb1a3b |
14 | 25c481ac81 |
15 | 147993eebd |
hex | ba442ede1 |
50000489953 has 2 divisors, whose sum is σ = 50000489954. Its totient is φ = 50000489952.
The previous prime is 50000489933. The next prime is 50000489989. The reversal of 50000489953 is 35998400005.
It is a happy number.
50000489953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28374728704 + 21625761249 = 168448^2 + 147057^2 .
It is a cyclic number.
It is not a de Polignac number, because 50000489953 - 25 = 50000489921 is a prime.
It is not a weakly prime, because it can be changed into another prime (50000489933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000244976 + 25000244977.
It is an arithmetic number, because the mean of its divisors is an integer number (25000244977).
Almost surely, 250000489953 is an apocalyptic number.
It is an amenable number.
50000489953 is a deficient number, since it is larger than the sum of its proper divisors (1).
50000489953 is an equidigital number, since it uses as much as digits as its factorization.
50000489953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 43.
Adding to 50000489953 its reverse (35998400005), we get a palindrome (85998889958).
The spelling of 50000489953 in words is "fifty billion, four hundred eighty-nine thousand, nine hundred fifty-three".
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