500013030000131 has 4 divisors (see below), whose sum is σ = 500771775114600. Its totient is φ = 499254284885664.

The previous prime is 500013030000101. The next prime is 500013030000137. The reversal of 500013030000131 is 131000030310005.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 500013030000131 - 2⁶ = 500013030000067 is a prime.

It is a super-2 number, since 2×500013030000131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (500013030000137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 379372556246 + ... + 379372557563.

It is an arithmetic number, because the mean of its divisors is an integer number (125192943778650).

Almost surely, 2^{500013030000131} is an apocalyptic number.

500013030000131 is a deficient number, since it is larger than the sum of its proper divisors (758745114469).

500013030000131 is an equidigital number, since it uses as much as digits as its factorization.

500013030000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 758745114468.

The product of its (nonzero) digits is 135, while the sum is 17.

Adding to 500013030000131 its reverse (131000030310005), we get a palindrome (631013060310136).

The spelling of 500013030000131 in words is "five hundred trillion, thirteen billion, thirty million, one hundred thirty-one", and thus it is an aban number.