Base | Representation |
---|---|
bin | 101110100100010100… |
… | …010100011001011111 |
3 | 11210001200111211100221 |
4 | 232210110110121133 |
5 | 1304400331230421 |
6 | 34545332102211 |
7 | 3420040100113 |
oct | 564424243137 |
9 | 153050454327 |
10 | 50001430111 |
11 | 1a22955a566 |
12 | 9835464967 |
13 | 493b150949 |
14 | 25c49c3743 |
15 | 1479a78841 |
hex | ba451465f |
50001430111 has 4 divisors (see below), whose sum is σ = 51352820152. Its totient is φ = 48650040072.
The previous prime is 50001430109. The next prime is 50001430159. The reversal of 50001430111 is 11103410005.
50001430111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50001430111 - 21 = 50001430109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50001430411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 675694965 + ... + 675695038.
It is an arithmetic number, because the mean of its divisors is an integer number (12838205038).
Almost surely, 250001430111 is an apocalyptic number.
50001430111 is a deficient number, since it is larger than the sum of its proper divisors (1351390041).
50001430111 is a wasteful number, since it uses less digits than its factorization.
50001430111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1351390040.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 50001430111 its reverse (11103410005), we get a palindrome (61104840116).
The spelling of 50001430111 in words is "fifty billion, one million, four hundred thirty thousand, one hundred eleven".
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