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5000300003 = 9371533593
BaseRepresentation
bin1001010100000101…
…01000010111100011
3110220110221120002102
410222002220113203
540220034100003
62144101441015
7234624564056
oct45202502743
913813846072
105000300003
1121365a2446
12b7671016b
13618c352ca
1435613ca9d
151e3eb5588
hex12a0a85e3

5000300003 has 4 divisors (see below), whose sum is σ = 5000842968. Its totient is φ = 4999757040.

The previous prime is 5000299961. The next prime is 5000300009. The reversal of 5000300003 is 3000030005.

5000300003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5000300003 - 214 = 5000283619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5000300009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257426 + ... + 276167.

It is an arithmetic number, because the mean of its divisors is an integer number (1250210742).

Almost surely, 25000300003 is an apocalyptic number.

5000300003 is a deficient number, since it is larger than the sum of its proper divisors (542965).

5000300003 is an equidigital number, since it uses as much as digits as its factorization.

5000300003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 542964.

The product of its (nonzero) digits is 45, while the sum is 11.

The square root of 5000300003 is about 70712.7994283920. The cubic root of 5000300003 is about 1710.0101458536.

Adding to 5000300003 its reverse (3000030005), we get a palindrome (8000330008).

The spelling of 5000300003 in words is "five billion, three hundred thousand, three".

Divisors: 1 9371 533593 5000300003