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500043550133 is a prime number
BaseRepresentation
bin1110100011011001110…
…10110000110110110101
31202210200220011021210102
413101230322300312311
531143042122101013
61021414500403445
751061355021561
oct7215472606665
91683626137712
10500043550133
11183081603346
1280ab36a6585
133820018849a
141a2b8d1c6a1
15d019886d58
hex746ceb0db5

500043550133 has 2 divisors, whose sum is σ = 500043550134. Its totient is φ = 500043550132.

The previous prime is 500043550093. The next prime is 500043550163. The reversal of 500043550133 is 331055340005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 487995853489 + 12047696644 = 698567^2 + 109762^2 .

It is a cyclic number.

It is not a de Polignac number, because 500043550133 - 228 = 499775114677 is a prime.

It is a super-2 number, since 2×5000435501332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 500043550096 and 500043550105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (500043550163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250021775066 + 250021775067.

It is an arithmetic number, because the mean of its divisors is an integer number (250021775067).

Almost surely, 2500043550133 is an apocalyptic number.

It is an amenable number.

500043550133 is a deficient number, since it is larger than the sum of its proper divisors (1).

500043550133 is an equidigital number, since it uses as much as digits as its factorization.

500043550133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 500043550133 its reverse (331055340005), we get a palindrome (831098890138).

The spelling of 500043550133 in words is "five hundred billion, forty-three million, five hundred fifty thousand, one hundred thirty-three".