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50009916217 is a prime number
BaseRepresentation
bin101110100100110100…
…101100001100111001
311210002021110222010011
4232210310230030321
51304410014304332
634550234021521
73420202163002
oct564464541471
9153067428104
1050009916217
111a233326278
1298382778a1
13493cb32401
1425c5b921a9
15147a6a2e47
hexba4d2c339

50009916217 has 2 divisors, whose sum is σ = 50009916218. Its totient is φ = 50009916216.

The previous prime is 50009916211. The next prime is 50009916223. The reversal of 50009916217 is 71261990005.

50009916217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (50009916211) and next prime (50009916223).

It can be written as a sum of positive squares in only one way, i.e., 48789741456 + 1220174761 = 220884^2 + 34931^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50009916217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50009916217.

It is not a weakly prime, because it can be changed into another prime (50009916211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25004958108 + 25004958109.

It is an arithmetic number, because the mean of its divisors is an integer number (25004958109).

Almost surely, 250009916217 is an apocalyptic number.

It is an amenable number.

50009916217 is a deficient number, since it is larger than the sum of its proper divisors (1).

50009916217 is an equidigital number, since it uses as much as digits as its factorization.

50009916217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34020, while the sum is 40.

The spelling of 50009916217 in words is "fifty billion, nine million, nine hundred sixteen thousand, two hundred seventeen".