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50011088401 is a prime number
BaseRepresentation
bin101110100100111001…
…001010011000010001
311210002100200112001101
4232210321022120101
51304410314312101
634550315104401
73420215144311
oct564471123021
9153070615041
1050011088401
111a233a56a1a
129838742101
134940152b01
1425c5db9441
15147a835401
hexba4e4a611

50011088401 has 2 divisors, whose sum is σ = 50011088402. Its totient is φ = 50011088400.

The previous prime is 50011088383. The next prime is 50011088429. The reversal of 50011088401 is 10488011005.

It is an a-pointer prime, because the next prime (50011088429) can be obtained adding 50011088401 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50003668225 + 7420176 = 223615^2 + 2724^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50011088401 is a prime.

It is a super-2 number, since 2×500110884012 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 50011088401.

It is not a weakly prime, because it can be changed into another prime (50011088201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25005544200 + 25005544201.

It is an arithmetic number, because the mean of its divisors is an integer number (25005544201).

Almost surely, 250011088401 is an apocalyptic number.

It is an amenable number.

50011088401 is a deficient number, since it is larger than the sum of its proper divisors (1).

50011088401 is an equidigital number, since it uses as much as digits as its factorization.

50011088401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 28.

Adding to 50011088401 its reverse (10488011005), we get a palindrome (60499099406).

The spelling of 50011088401 in words is "fifty billion, eleven million, eighty-eight thousand, four hundred one".