Base | Representation |
---|---|
bin | 101110100100111101… |
… | …001011101101100001 |
3 | 11210002102200001220121 |
4 | 232210331023231201 |
5 | 1304411102024213 |
6 | 34550353440241 |
7 | 3420230124301 |
oct | 564475135541 |
9 | 153072601817 |
10 | 50012142433 |
11 | 1a234606920 |
12 | 9838b70081 |
13 | 49404317b6 |
14 | 25c61b1601 |
15 | 147a99288d |
hex | ba4f4bb61 |
50012142433 has 4 divisors (see below), whose sum is σ = 54558700848. Its totient is φ = 45465584020.
The previous prime is 50012142413. The next prime is 50012142541. The reversal of 50012142433 is 33424121005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50012142433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50012142398 and 50012142407.
It is not an unprimeable number, because it can be changed into a prime (50012142413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2273279191 + ... + 2273279212.
It is an arithmetic number, because the mean of its divisors is an integer number (13639675212).
Almost surely, 250012142433 is an apocalyptic number.
It is an amenable number.
50012142433 is a deficient number, since it is larger than the sum of its proper divisors (4546558415).
50012142433 is a wasteful number, since it uses less digits than its factorization.
50012142433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4546558414.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 50012142433 its reverse (33424121005), we get a palindrome (83436263438).
The spelling of 50012142433 in words is "fifty billion, twelve million, one hundred forty-two thousand, four hundred thirty-three".
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