Base | Representation |
---|---|
bin | 101110100101000000… |
… | …111000011110110001 |
3 | 11210002111111100020102 |
4 | 232211000320132301 |
5 | 1304411324042431 |
6 | 34550430322145 |
7 | 3420241303601 |
oct | 564500703661 |
9 | 153074440212 |
10 | 50013112241 |
11 | 1a235109514 |
12 | 9839359355 |
13 | 49406b1051 |
14 | 25c6384c01 |
15 | 147aad4dcb |
hex | ba50387b1 |
50013112241 has 2 divisors, whose sum is σ = 50013112242. Its totient is φ = 50013112240.
The previous prime is 50013112199. The next prime is 50013112267. The reversal of 50013112241 is 14221131005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37792915216 + 12220197025 = 194404^2 + 110545^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50013112241 is a prime.
It is a super-2 number, since 2×500131122412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50013112741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25006556120 + 25006556121.
It is an arithmetic number, because the mean of its divisors is an integer number (25006556121).
Almost surely, 250013112241 is an apocalyptic number.
It is an amenable number.
50013112241 is a deficient number, since it is larger than the sum of its proper divisors (1).
50013112241 is an equidigital number, since it uses as much as digits as its factorization.
50013112241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 50013112241 its reverse (14221131005), we get a palindrome (64234243246).
The spelling of 50013112241 in words is "fifty billion, thirteen million, one hundred twelve thousand, two hundred forty-one".
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