Base | Representation |
---|---|
bin | 10110101111110001101110… |
… | …00101101001001011111111 |
3 | 20120002212122200222120221011 |
4 | 23113320313011221023333 |
5 | 23024012143004334034 |
6 | 254214531200220051 |
7 | 13351556016213436 |
oct | 1327706705511377 |
9 | 216085580876834 |
10 | 50020113355519 |
11 | 14a35457a7085a |
12 | 573a29690a627 |
13 | 21bab51739388 |
14 | c4cdb499a11d |
15 | 5bb21081c864 |
hex | 2d7e371692ff |
50020113355519 has 2 divisors, whose sum is σ = 50020113355520. Its totient is φ = 50020113355518.
The previous prime is 50020113355489. The next prime is 50020113355523. The reversal of 50020113355519 is 91555331102005.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50020113355519 - 211 = 50020113353471 is a prime.
It is a super-2 number, since 2×500201133555192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50020113355549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25010056677759 + 25010056677760.
It is an arithmetic number, because the mean of its divisors is an integer number (25010056677760).
Almost surely, 250020113355519 is an apocalyptic number.
50020113355519 is a deficient number, since it is larger than the sum of its proper divisors (1).
50020113355519 is an equidigital number, since it uses as much as digits as its factorization.
50020113355519 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 101250, while the sum is 40.
The spelling of 50020113355519 in words is "fifty trillion, twenty billion, one hundred thirteen million, three hundred fifty-five thousand, five hundred nineteen".
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