Base | Representation |
---|---|
bin | 101110100101011011… |
… | …110011111110111111 |
3 | 11210002222210000000021 |
4 | 232211123303332333 |
5 | 1304420130443321 |
6 | 34551241513011 |
7 | 3420355305256 |
oct | 564533637677 |
9 | 153088700007 |
10 | 50020171711 |
11 | 1a2390a0394 |
12 | 983b7a2767 |
13 | 4941cb3353 |
14 | 25c72a179d |
15 | 147b52b941 |
hex | ba56f3fbf |
50020171711 has 2 divisors, whose sum is σ = 50020171712. Its totient is φ = 50020171710.
The previous prime is 50020171687. The next prime is 50020171727. The reversal of 50020171711 is 11717102005.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50020171711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50020171741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25010085855 + 25010085856.
It is an arithmetic number, because the mean of its divisors is an integer number (25010085856).
Almost surely, 250020171711 is an apocalyptic number.
50020171711 is a deficient number, since it is larger than the sum of its proper divisors (1).
50020171711 is an equidigital number, since it uses as much as digits as its factorization.
50020171711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 490, while the sum is 25.
Adding to 50020171711 its reverse (11717102005), we get a palindrome (61737273716).
The spelling of 50020171711 in words is "fifty billion, twenty million, one hundred seventy-one thousand, seven hundred eleven".
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