Base | Representation |
---|---|
bin | 101110100101011101… |
… | …001011101110101101 |
3 | 11210010000110021000121 |
4 | 232211131023232231 |
5 | 1304420223443432 |
6 | 34551253324541 |
7 | 3420361333144 |
oct | 564535135655 |
9 | 153100407017 |
10 | 50020531117 |
11 | 1a239316417 |
12 | 983b936751 |
13 | 49420aab0b |
14 | 25c735675b |
15 | 147b59d197 |
hex | ba574bbad |
50020531117 has 2 divisors, whose sum is σ = 50020531118. Its totient is φ = 50020531116.
The previous prime is 50020531109. The next prime is 50020531153. The reversal of 50020531117 is 71113502005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39380814916 + 10639716201 = 198446^2 + 103149^2 .
It is a cyclic number.
It is not a de Polignac number, because 50020531117 - 23 = 50020531109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50020531091 and 50020531100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50020531817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25010265558 + 25010265559.
It is an arithmetic number, because the mean of its divisors is an integer number (25010265559).
Almost surely, 250020531117 is an apocalyptic number.
It is an amenable number.
50020531117 is a deficient number, since it is larger than the sum of its proper divisors (1).
50020531117 is an equidigital number, since it uses as much as digits as its factorization.
50020531117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1050, while the sum is 25.
The spelling of 50020531117 in words is "fifty billion, twenty million, five hundred thirty-one thousand, one hundred seventeen".
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