Base | Representation |
---|---|
bin | 101110100101101000… |
… | …100101011100001101 |
3 | 11210010020002010000110 |
4 | 232211220211130031 |
5 | 1304422010120023 |
6 | 34551441350233 |
7 | 3420425622135 |
oct | 564550453415 |
9 | 153106063013 |
10 | 50023520013 |
11 | 1a23aa77a85 |
12 | 9840938379 |
13 | 49428b63ac |
14 | 25c78d3ac5 |
15 | 147b98da93 |
hex | ba5a2570d |
50023520013 has 4 divisors (see below), whose sum is σ = 66698026688. Its totient is φ = 33349013340.
The previous prime is 50023519991. The next prime is 50023520033. The reversal of 50023520013 is 31002532005.
50023520013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 50023520013 - 28 = 50023519757 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50023520033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8337253333 + ... + 8337253338.
It is an arithmetic number, because the mean of its divisors is an integer number (16674506672).
Almost surely, 250023520013 is an apocalyptic number.
It is an amenable number.
50023520013 is a deficient number, since it is larger than the sum of its proper divisors (16674506675).
50023520013 is a wasteful number, since it uses less digits than its factorization.
50023520013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16674506674.
The product of its (nonzero) digits is 900, while the sum is 21.
The spelling of 50023520013 in words is "fifty billion, twenty-three million, five hundred twenty thousand, thirteen".
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