Base | Representation |
---|---|
bin | 101110100110000111… |
… | …110110000000011011 |
3 | 11210010210111102111201 |
4 | 232212013312000123 |
5 | 1304431104324311 |
6 | 34552333135031 |
7 | 3420555361234 |
oct | 564607660033 |
9 | 153123442451 |
10 | 50031714331 |
11 | 1a244664545 |
12 | 984362a477 |
13 | 49444c50c1 |
14 | 25c8a2808b |
15 | 147c55b9c1 |
hex | ba61f601b |
50031714331 has 2 divisors, whose sum is σ = 50031714332. Its totient is φ = 50031714330.
The previous prime is 50031714329. The next prime is 50031714347. The reversal of 50031714331 is 13341713005.
50031714331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50031714331 - 21 = 50031714329 is a prime.
It is a super-2 number, since 2×500317143312 (a number of 22 digits) contains 22 as substring.
Together with 50031714329, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 50031714331.
It is not a weakly prime, because it can be changed into another prime (50031714311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25015857165 + 25015857166.
It is an arithmetic number, because the mean of its divisors is an integer number (25015857166).
Almost surely, 250031714331 is an apocalyptic number.
50031714331 is a deficient number, since it is larger than the sum of its proper divisors (1).
50031714331 is an equidigital number, since it uses as much as digits as its factorization.
50031714331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 28.
The spelling of 50031714331 in words is "fifty billion, thirty-one million, seven hundred fourteen thousand, three hundred thirty-one".
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