Base | Representation |
---|---|
bin | 101110100110001101… |
… | …010010111001111101 |
3 | 11210010220012000211222 |
4 | 232212031102321331 |
5 | 1304431441042141 |
6 | 34552423523125 |
7 | 3420603462542 |
oct | 564615227175 |
9 | 153126160758 |
10 | 50033143421 |
11 | 1a245450208 |
12 | 9843bb94a5 |
13 | 49448a5711 |
14 | 25c8cbabc9 |
15 | 147c74014b |
hex | ba6352e7d |
50033143421 has 4 divisors (see below), whose sum is σ = 50033646144. Its totient is φ = 50032640700.
The previous prime is 50033143417. The next prime is 50033143429. The reversal of 50033143421 is 12434133005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 50033143421 - 22 = 50033143417 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50033143429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46325 + ... + 319706.
It is an arithmetic number, because the mean of its divisors is an integer number (12508411536).
Almost surely, 250033143421 is an apocalyptic number.
It is an amenable number.
50033143421 is a deficient number, since it is larger than the sum of its proper divisors (502723).
50033143421 is a wasteful number, since it uses less digits than its factorization.
50033143421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 502722.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 50033143421 its reverse (12434133005), we get a palindrome (62467276426).
The spelling of 50033143421 in words is "fifty billion, thirty-three million, one hundred forty-three thousand, four hundred twenty-one".
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