Base | Representation |
---|---|
bin | 101110100110010100… |
… | …110100010101011001 |
3 | 11210011000220012211111 |
4 | 232212110310111121 |
5 | 1304432442142403 |
6 | 34552534100321 |
7 | 3420626314606 |
oct | 564624642531 |
9 | 153130805744 |
10 | 50035115353 |
11 | 1a246577803 |
12 | 98447aa6a1 |
13 | 4945116142 |
14 | 25c92716ad |
15 | 147c9ce56d |
hex | ba6534559 |
50035115353 has 2 divisors, whose sum is σ = 50035115354. Its totient is φ = 50035115352.
The previous prime is 50035115257. The next prime is 50035115419. The reversal of 50035115353 is 35351153005.
It is a happy number.
50035115353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32685747264 + 17349368089 = 180792^2 + 131717^2 .
It is a cyclic number.
It is not a de Polignac number, because 50035115353 - 221 = 50033018201 is a prime.
It is not a weakly prime, because it can be changed into another prime (50035115153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25017557676 + 25017557677.
It is an arithmetic number, because the mean of its divisors is an integer number (25017557677).
Almost surely, 250035115353 is an apocalyptic number.
It is an amenable number.
50035115353 is a deficient number, since it is larger than the sum of its proper divisors (1).
50035115353 is an equidigital number, since it uses as much as digits as its factorization.
50035115353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16875, while the sum is 31.
Adding to 50035115353 its reverse (35351153005), we get a palindrome (85386268358).
The spelling of 50035115353 in words is "fifty billion, thirty-five million, one hundred fifteen thousand, three hundred fifty-three".
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