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50035325153 = 114548665923
BaseRepresentation
bin101110100110010101…
…100111100011100001
311210011001021212121212
4232212111213203201
51304433020401103
634552542355505
73420631150352
oct564625474341
9153131255555
1050035325153
111a2467003a0
12984488bb95
13494518a798
1425c92c7d29
15147ca217d8
hexba65678e1

50035325153 has 4 divisors (see below), whose sum is σ = 54583991088. Its totient is φ = 45486659220.

The previous prime is 50035325147. The next prime is 50035325161. The reversal of 50035325153 is 35152353005.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50035325153 - 224 = 50018547937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (50035325113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2274332951 + ... + 2274332972.

It is an arithmetic number, because the mean of its divisors is an integer number (13645997772).

Almost surely, 250035325153 is an apocalyptic number.

It is an amenable number.

50035325153 is a deficient number, since it is larger than the sum of its proper divisors (4548665935).

50035325153 is a wasteful number, since it uses less digits than its factorization.

50035325153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4548665934.

The product of its (nonzero) digits is 33750, while the sum is 32.

Adding to 50035325153 its reverse (35152353005), we get a palindrome (85187678158).

The spelling of 50035325153 in words is "fifty billion, thirty-five million, three hundred twenty-five thousand, one hundred fifty-three".

Divisors: 1 11 4548665923 50035325153