Base | Representation |
---|---|
bin | 101110100110011110… |
… | …010111000111110101 |
3 | 11210011012121022122022 |
4 | 232212132113013311 |
5 | 1304434112222031 |
6 | 34553103442525 |
7 | 3420656504501 |
oct | 564636270765 |
9 | 153135538568 |
10 | 50037617141 |
11 | 1a247a263a6 |
12 | 98455b6445 |
13 | 49457b0aa5 |
14 | 25c9723301 |
15 | 147cd2597b |
hex | ba67971f5 |
50037617141 has 4 divisors (see below), whose sum is σ = 50742372384. Its totient is φ = 49332861900.
The previous prime is 50037617137. The next prime is 50037617197. The reversal of 50037617141 is 14171673005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50037617141 - 22 = 50037617137 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50037617101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352377515 + ... + 352377656.
It is an arithmetic number, because the mean of its divisors is an integer number (12685593096).
Almost surely, 250037617141 is an apocalyptic number.
It is an amenable number.
50037617141 is a deficient number, since it is larger than the sum of its proper divisors (704755243).
50037617141 is an equidigital number, since it uses as much as digits as its factorization.
50037617141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 704755242.
The product of its (nonzero) digits is 17640, while the sum is 35.
The spelling of 50037617141 in words is "fifty billion, thirty-seven million, six hundred seventeen thousand, one hundred forty-one".
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