Base | Representation |
---|---|
bin | 100100011010001010110… |
… | …1110001100110101111111 |
3 | 122201101012110022212212011 |
4 | 1020310111232030311333 |
5 | 1123441143320120412 |
6 | 14350450110552051 |
7 | 1024345550345644 |
oct | 110642556146577 |
9 | 18641173285764 |
10 | 5004001332607 |
11 | 165a204330a12 |
12 | 689985b08627 |
13 | 2a3b4c0613b4 |
14 | 1342a2d65dcb |
15 | 8a273b5b7a7 |
hex | 48d15b8cd7f |
5004001332607 has 2 divisors, whose sum is σ = 5004001332608. Its totient is φ = 5004001332606.
The previous prime is 5004001332437. The next prime is 5004001332611. The reversal of 5004001332607 is 7062331004005.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5004001332607 - 239 = 4454245518719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5004001335607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502000666303 + 2502000666304.
It is an arithmetic number, because the mean of its divisors is an integer number (2502000666304).
Almost surely, 25004001332607 is an apocalyptic number.
5004001332607 is a deficient number, since it is larger than the sum of its proper divisors (1).
5004001332607 is an equidigital number, since it uses as much as digits as its factorization.
5004001332607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 5004001332607 in words is "five trillion, four billion, one million, three hundred thirty-two thousand, six hundred seven".
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