50041311433433 has 4 divisors (see below), whose sum is σ = 50435337507840. Its totient is φ = 49647285359028.

The previous prime is 50041311433429. The next prime is 50041311433459. The reversal of 50041311433433 is 33433411314005.

50041311433433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 50041311433433 - 2² = 50041311433429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50041311433393 and 50041311433402.

It is not an unprimeable number, because it can be changed into a prime (50041311433933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197013037013 + ... + 197013037266.

It is an arithmetic number, because the mean of its divisors is an integer number (12608834376960).

Almost surely, 2^{50041311433433} is an apocalyptic number.

It is an amenable number.

50041311433433 is a deficient number, since it is larger than the sum of its proper divisors (394026074407).

50041311433433 is a wasteful number, since it uses less digits than its factorization.

50041311433433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 394026074406.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 50041311433433 its reverse (33433411314005), we get a palindrome (83474722747438).

The spelling of 50041311433433 in words is "fifty trillion, forty-one billion, three hundred eleven million, four hundred thirty-three thousand, four hundred thirty-three".