Base | Representation |
---|---|
bin | 101110100110110100… |
… | …100011000010111111 |
3 | 11210011121112210201002 |
4 | 232212310203002333 |
5 | 1304442104330101 |
6 | 34553432240515 |
7 | 3421060110005 |
oct | 564664430277 |
9 | 153147483632 |
10 | 50043433151 |
11 | 1a250239018 |
12 | 984754013b |
13 | 4946a6910a |
14 | 25ca3d8a75 |
15 | 147d5c3d6b |
hex | ba6d230bf |
50043433151 has 2 divisors, whose sum is σ = 50043433152. Its totient is φ = 50043433150.
The previous prime is 50043433109. The next prime is 50043433169. The reversal of 50043433151 is 15133434005.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50043433151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50043433351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25021716575 + 25021716576.
It is an arithmetic number, because the mean of its divisors is an integer number (25021716576).
Almost surely, 250043433151 is an apocalyptic number.
50043433151 is a deficient number, since it is larger than the sum of its proper divisors (1).
50043433151 is an equidigital number, since it uses as much as digits as its factorization.
50043433151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 50043433151 its reverse (15133434005), we get a palindrome (65176867156).
The spelling of 50043433151 in words is "fifty billion, forty-three million, four hundred thirty-three thousand, one hundred fifty-one".
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