Base | Representation |
---|---|
bin | 101110100111001111… |
… | …101101110010011001 |
3 | 11210012002221122002111 |
4 | 232213033231302121 |
5 | 1310000420230113 |
6 | 34554245032321 |
7 | 3421204461343 |
oct | 564717556231 |
9 | 153162848074 |
10 | 50050555033 |
11 | 1a254262876 |
12 | 98499b56a1 |
13 | 494839094b |
14 | 25cb330293 |
15 | 147e02e13d |
hex | ba73edc99 |
50050555033 has 2 divisors, whose sum is σ = 50050555034. Its totient is φ = 50050555032.
The previous prime is 50050555031. The next prime is 50050555097. The reversal of 50050555033 is 33055505005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47644848729 + 2405706304 = 218277^2 + 49048^2 .
It is a cyclic number.
It is not a de Polignac number, because 50050555033 - 21 = 50050555031 is a prime.
It is a super-2 number, since 2×500505550332 (a number of 22 digits) contains 22 as substring.
Together with 50050555031, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 50050554986 and 50050555004.
It is not a weakly prime, because it can be changed into another prime (50050555031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025277516 + 25025277517.
It is an arithmetic number, because the mean of its divisors is an integer number (25025277517).
Almost surely, 250050555033 is an apocalyptic number.
It is an amenable number.
50050555033 is a deficient number, since it is larger than the sum of its proper divisors (1).
50050555033 is an equidigital number, since it uses as much as digits as its factorization.
50050555033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28125, while the sum is 31.
The spelling of 50050555033 in words is "fifty billion, fifty million, five hundred fifty-five thousand, thirty-three".
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