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50052750252853 is a prime number
BaseRepresentation
bin10110110000101110100000…
…11001100001101100110101
320120012222220020001202102111
423120113100121201230311
523030031013031042403
6254241525510211021
713354122545236555
oct1330272031415465
9216188806052374
1050052750252853
1114a48285710887
125744684953a71
1321c0c531c294a
14c507cd2cd165
155bbec0bb456d
hex2d85d0661b35

50052750252853 has 2 divisors, whose sum is σ = 50052750252854. Its totient is φ = 50052750252852.

The previous prime is 50052750252811. The next prime is 50052750252893. The reversal of 50052750252853 is 35825205725005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45453175158609 + 4599575094244 = 6741897^2 + 2144662^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50052750252853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50052750252797 and 50052750252806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50052750252803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25026375126426 + 25026375126427.

It is an arithmetic number, because the mean of its divisors is an integer number (25026375126427).

Almost surely, 250052750252853 is an apocalyptic number.

It is an amenable number.

50052750252853 is a deficient number, since it is larger than the sum of its proper divisors (1).

50052750252853 is an equidigital number, since it uses as much as digits as its factorization.

50052750252853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4200000, while the sum is 49.

Adding to 50052750252853 its reverse (35825205725005), we get a palindrome (85877955977858).

The spelling of 50052750252853 in words is "fifty trillion, fifty-two billion, seven hundred fifty million, two hundred fifty-two thousand, eight hundred fifty-three".