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50052752755503 = 316684250918501
BaseRepresentation
bin10110110000101110100001…
…00011000100101100101111
320120012222220101202220102020
423120113100203010230233
523030031014201134003
6254241530040001223
713354122605432121
oct1330272043045457
9216188811686366
1050052752755503
1114a48287070093
125744685760213
1321c0c5388aac4
14c507cd781211
155bbec100ad53
hex2d85d08c4b2f

50052752755503 has 4 divisors (see below), whose sum is σ = 66737003674008. Its totient is φ = 33368501837000.

The previous prime is 50052752755487. The next prime is 50052752755513. The reversal of 50052752755503 is 30555725725005.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50052752755503 - 24 = 50052752755487 is a prime.

It is a super-3 number, since 3×500527527555033 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50052752755513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8342125459248 + ... + 8342125459253.

It is an arithmetic number, because the mean of its divisors is an integer number (16684250918502).

Almost surely, 250052752755503 is an apocalyptic number.

50052752755503 is a deficient number, since it is larger than the sum of its proper divisors (16684250918505).

50052752755503 is a wasteful number, since it uses less digits than its factorization.

50052752755503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16684250918504.

The product of its (nonzero) digits is 9187500, while the sum is 51.

The spelling of 50052752755503 in words is "fifty trillion, fifty-two billion, seven hundred fifty-two million, seven hundred fifty-five thousand, five hundred three".

Divisors: 1 3 16684250918501 50052752755503