Base | Representation |
---|---|
bin | 10110110000101110100001… |
… | …00011000100101100101111 |
3 | 20120012222220101202220102020 |
4 | 23120113100203010230233 |
5 | 23030031014201134003 |
6 | 254241530040001223 |
7 | 13354122605432121 |
oct | 1330272043045457 |
9 | 216188811686366 |
10 | 50052752755503 |
11 | 14a48287070093 |
12 | 5744685760213 |
13 | 21c0c5388aac4 |
14 | c507cd781211 |
15 | 5bbec100ad53 |
hex | 2d85d08c4b2f |
50052752755503 has 4 divisors (see below), whose sum is σ = 66737003674008. Its totient is φ = 33368501837000.
The previous prime is 50052752755487. The next prime is 50052752755513. The reversal of 50052752755503 is 30555725725005.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50052752755503 - 24 = 50052752755487 is a prime.
It is a super-3 number, since 3×500527527555033 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50052752755513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8342125459248 + ... + 8342125459253.
It is an arithmetic number, because the mean of its divisors is an integer number (16684250918502).
Almost surely, 250052752755503 is an apocalyptic number.
50052752755503 is a deficient number, since it is larger than the sum of its proper divisors (16684250918505).
50052752755503 is a wasteful number, since it uses less digits than its factorization.
50052752755503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16684250918504.
The product of its (nonzero) digits is 9187500, while the sum is 51.
The spelling of 50052752755503 in words is "fifty trillion, fifty-two billion, seven hundred fifty-two million, seven hundred fifty-five thousand, five hundred three".
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