Base | Representation |
---|---|
bin | 101110100111011010… |
… | …100101111100000111 |
3 | 11210012022022111112022 |
4 | 232213122211330013 |
5 | 1310002133001341 |
6 | 34554430113355 |
7 | 3421240635515 |
oct | 564732457407 |
9 | 153168274468 |
10 | 50053406471 |
11 | 1a255930132 |
12 | 984a94b85b |
13 | 4948b4b7a3 |
14 | 25cb8734b5 |
15 | 147e3e3e4b |
hex | ba76a5f07 |
50053406471 has 4 divisors (see below), whose sum is σ = 50268228192. Its totient is φ = 49838584752.
The previous prime is 50053406461. The next prime is 50053406521. The reversal of 50053406471 is 17460435005.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50053406471 is a prime.
It is a super-3 number, since 3×500534064713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50053406461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107410511 + ... + 107410976.
It is an arithmetic number, because the mean of its divisors is an integer number (12567057048).
Almost surely, 250053406471 is an apocalyptic number.
50053406471 is a deficient number, since it is larger than the sum of its proper divisors (214821721).
50053406471 is a wasteful number, since it uses less digits than its factorization.
50053406471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 214821720.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 50053406471 in words is "fifty billion, fifty-three million, four hundred six thousand, four hundred seventy-one".
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