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50055000493 is a prime number
BaseRepresentation
bin101110100111100000…
…101011000110101101
311210012102022111010011
4232213200223012231
51310003040003433
634554524213221
73421260325021
oct564740530655
9153172274104
1050055000493
111a256819803
12984b39a211
1349492891b4
1425cbb6a381
15147e60b3cd
hexba782b1ad

50055000493 has 2 divisors, whose sum is σ = 50055000494. Its totient is φ = 50055000492.

The previous prime is 50055000473. The next prime is 50055000503. The reversal of 50055000493 is 39400055005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50031400329 + 23600164 = 223677^2 + 4858^2 .

It is a cyclic number.

It is not a de Polignac number, because 50055000493 - 25 = 50055000461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50055000473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25027500246 + 25027500247.

It is an arithmetic number, because the mean of its divisors is an integer number (25027500247).

Almost surely, 250055000493 is an apocalyptic number.

It is an amenable number.

50055000493 is a deficient number, since it is larger than the sum of its proper divisors (1).

50055000493 is an equidigital number, since it uses as much as digits as its factorization.

50055000493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 50055000493 its reverse (39400055005), we get a palindrome (89455055498).

The spelling of 50055000493 in words is "fifty billion, fifty-five million, four hundred ninety-three", and thus it is an aban number.