Base | Representation |
---|---|
bin | 1110100100101100001… |
… | …10001001011001010001 |
3 | 1202212111001010002202112 |
4 | 13102112012021121101 |
5 | 31201001001300311 |
6 | 1022011215555105 |
7 | 51114444113426 |
oct | 7222606113121 |
9 | 1685431102675 |
10 | 500734400081 |
11 | 1833a6573113 |
12 | 81066b2ba95 |
13 | 382b0342b36 |
14 | 1a342993d4d |
15 | d05a34d28b |
hex | 7496189651 |
500734400081 has 2 divisors, whose sum is σ = 500734400082. Its totient is φ = 500734400080.
The previous prime is 500734400063. The next prime is 500734400123. The reversal of 500734400081 is 180004437005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 255015910081 + 245718490000 = 504991^2 + 495700^2 .
It is a cyclic number.
It is not a de Polignac number, because 500734400081 - 222 = 500730205777 is a prime.
It is a super-2 number, since 2×5007344000812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (500734400281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250367200040 + 250367200041.
It is an arithmetic number, because the mean of its divisors is an integer number (250367200041).
Almost surely, 2500734400081 is an apocalyptic number.
It is an amenable number.
500734400081 is a deficient number, since it is larger than the sum of its proper divisors (1).
500734400081 is an equidigital number, since it uses as much as digits as its factorization.
500734400081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 500734400081 its reverse (180004437005), we get a palindrome (680738837086).
The spelling of 500734400081 in words is "five hundred billion, seven hundred thirty-four million, four hundred thousand, eighty-one".
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