Base | Representation |
---|---|
bin | 10110110001010111101011… |
… | …10100111011111110111111 |
3 | 20120022002221121100021012121 |
4 | 23120223311310323332333 |
5 | 23030411244334004441 |
6 | 254300023033343411 |
7 | 13355534352613543 |
oct | 1330536564737677 |
9 | 216262847307177 |
10 | 50074853031871 |
11 | 14a566980a68a8 |
12 | 5748a12b67b67 |
13 | 21c306641c305 |
14 | c518c8985a23 |
15 | 5bc866345dd1 |
hex | 2d8af5d3bfbf |
50074853031871 has 2 divisors, whose sum is σ = 50074853031872. Its totient is φ = 50074853031870.
The previous prime is 50074853031817. The next prime is 50074853031947. The reversal of 50074853031871 is 17813035847005.
Together with previous prime (50074853031817) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50074853031871 - 215 = 50074852999103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50074853031811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25037426515935 + 25037426515936.
It is an arithmetic number, because the mean of its divisors is an integer number (25037426515936).
Almost surely, 250074853031871 is an apocalyptic number.
50074853031871 is a deficient number, since it is larger than the sum of its proper divisors (1).
50074853031871 is an equidigital number, since it uses as much as digits as its factorization.
50074853031871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2822400, while the sum is 52.
Adding to 50074853031871 its reverse (17813035847005), we get a palindrome (67887888878876).
The spelling of 50074853031871 in words is "fifty trillion, seventy-four billion, eight hundred fifty-three million, thirty-one thousand, eight hundred seventy-one".
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