Base | Representation |
---|---|
bin | 101110101010001100… |
… | …100010111001100011 |
3 | 11210022120002112011201 |
4 | 232222030202321203 |
5 | 1310101103240101 |
6 | 35003214022031 |
7 | 3422345306122 |
oct | 565214427143 |
9 | 153276075151 |
10 | 50100055651 |
11 | 1a27a1a2378 |
12 | 98624a7917 |
13 | 4955702959 |
14 | 25d3b37ab9 |
15 | 148355ae01 |
hex | baa322e63 |
50100055651 has 4 divisors (see below), whose sum is σ = 50117631304. Its totient is φ = 50082480000.
The previous prime is 50100055631. The next prime is 50100055667. The reversal of 50100055651 is 15655000105.
50100055651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15655000105 = 5 ⋅3131000021.
It is a cyclic number.
It is not a de Polignac number, because 50100055651 - 211 = 50100053603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50100055631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8783550 + ... + 8789251.
It is an arithmetic number, because the mean of its divisors is an integer number (12529407826).
Almost surely, 250100055651 is an apocalyptic number.
50100055651 is a deficient number, since it is larger than the sum of its proper divisors (17575653).
50100055651 is a wasteful number, since it uses less digits than its factorization.
50100055651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17575652.
The product of its (nonzero) digits is 3750, while the sum is 28.
Adding to 50100055651 its reverse (15655000105), we get a palindrome (65755055756).
The spelling of 50100055651 in words is "fifty billion, one hundred million, fifty-five thousand, six hundred fifty-one".
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