Base | Representation |
---|---|
bin | 10110110010010000110010… |
… | …01011110110000010110011 |
3 | 20120102001002012201221112221 |
4 | 23121020121023312002303 |
5 | 23031412041304313413 |
6 | 254322053132301511 |
7 | 13361001162256435 |
oct | 1331103113660263 |
9 | 216361065657487 |
10 | 50105511010483 |
11 | 14a6869a798a05 |
12 | 575294a311897 |
13 | 21c5c10bccb66 |
14 | c5319654a655 |
15 | 5bd55cae168d |
hex | 2d92192f60b3 |
50105511010483 has 2 divisors, whose sum is σ = 50105511010484. Its totient is φ = 50105511010482.
The previous prime is 50105511010469. The next prime is 50105511010517. The reversal of 50105511010483 is 38401011550105.
It is an a-pointer prime, because the next prime (50105511010517) can be obtained adding 50105511010483 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50105511010483 - 213 = 50105511002291 is a prime.
It is not a weakly prime, because it can be changed into another prime (50105511010433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25052755505241 + 25052755505242.
It is an arithmetic number, because the mean of its divisors is an integer number (25052755505242).
Almost surely, 250105511010483 is an apocalyptic number.
50105511010483 is a deficient number, since it is larger than the sum of its proper divisors (1).
50105511010483 is an equidigital number, since it uses as much as digits as its factorization.
50105511010483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 34.
Adding to 50105511010483 its reverse (38401011550105), we get a palindrome (88506522560588).
The spelling of 50105511010483 in words is "fifty trillion, one hundred five billion, five hundred eleven million, ten thousand, four hundred eighty-three".
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