Base | Representation |
---|---|
bin | 101110101010110011… |
… | …000000011100001001 |
3 | 11210100021001202201112 |
4 | 232222303000130021 |
5 | 1310111143404441 |
6 | 35004214100105 |
7 | 3422530101101 |
oct | 565263003411 |
9 | 153307052645 |
10 | 50110138121 |
11 | 1a28495949a |
12 | 986594a635 |
13 | 4957822c04 |
14 | 25d5200201 |
15 | 148439d4eb |
hex | baacc0709 |
50110138121 has 2 divisors, whose sum is σ = 50110138122. Its totient is φ = 50110138120.
The previous prime is 50110138063. The next prime is 50110138151. The reversal of 50110138121 is 12183101105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30772176400 + 19337961721 = 175420^2 + 139061^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50110138121 is a prime.
It is a super-2 number, since 2×501101381212 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50110138151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25055069060 + 25055069061.
It is an arithmetic number, because the mean of its divisors is an integer number (25055069061).
Almost surely, 250110138121 is an apocalyptic number.
It is an amenable number.
50110138121 is a deficient number, since it is larger than the sum of its proper divisors (1).
50110138121 is an equidigital number, since it uses as much as digits as its factorization.
50110138121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 50110138121 its reverse (12183101105), we get a palindrome (62293239226).
The spelling of 50110138121 in words is "fifty billion, one hundred ten million, one hundred thirty-eight thousand, one hundred twenty-one".
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