5011221113 has 4 divisors (see below), whose sum is σ = 5011859328. Its totient is φ = 5010582900.

The previous prime is 5011221097. The next prime is 5011221157. The reversal of 5011221113 is 3111221105.

5011221113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5011221113 - 2⁴ = 5011221097 is a prime.

It is a super-2 number, since 2×5011221113² = 50224674086753917538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5011221091 and 5011221100.

It is not an unprimeable number, because it can be changed into a prime (5011221013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307181 + ... + 323082.

It is an arithmetic number, because the mean of its divisors is an integer number (1252964832).

Almost surely, 2^5011221113 is an apocalyptic number.

It is an amenable number.

5011221113 is a deficient number, since it is larger than the sum of its proper divisors (638215).

5011221113 is an equidigital number, since it uses as much as digits as its factorization.

5011221113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 638214.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 5011221113 is about 70789.9789023842. The cubic root of 5011221113 is about 1711.2541798281.

Adding to 5011221113 its reverse (3111221105), we get a palindrome (8122442218).

The spelling of 5011221113 in words is "five billion, eleven million, two hundred twenty-one thousand, one hundred thirteen".