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5011340014 = 23767720811
BaseRepresentation
bin1001010101011001…
…01111101011101110
3110221020201110010201
410222230233223232
540230400340024
62145134224114
7235120454512
oct45254575356
913836643121
105011340014
112141852a1a
12b7a35503a
1361b2cc365
143577b4142
151e4e46744
hex12ab2faee

5011340014 has 8 divisors (see below), whose sum is σ = 7720172568. Its totient is φ = 2437949160.

The previous prime is 5011339979. The next prime is 5011340101. The reversal of 5011340014 is 4100431105.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×50113400142 = 50227057471835040392, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5011339973 and 5011340000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33860332 + ... + 33860479.

It is an arithmetic number, because the mean of its divisors is an integer number (965021571).

Almost surely, 25011340014 is an apocalyptic number.

5011340014 is a deficient number, since it is larger than the sum of its proper divisors (2708832554).

5011340014 is a wasteful number, since it uses less digits than its factorization.

5011340014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67720850.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 5011340014 is about 70790.8187125986. The cubic root of 5011340014 is about 1711.2677140027.

Adding to 5011340014 its reverse (4100431105), we get a palindrome (9111771119).

The spelling of 5011340014 in words is "five billion, eleven million, three hundred forty thousand, fourteen".

Divisors: 1 2 37 74 67720811 135441622 2505670007 5011340014