5011403533 has 4 divisors (see below), whose sum is σ = 5019660160. Its totient is φ = 5003146908.

The previous prime is 5011403513. The next prime is 5011403561. The reversal of 5011403533 is 3353041105.

5011403533 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5011403533 is a prime.

It is a super-2 number, since 2×5011403533² = 50228330741129764178, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5011403498 and 5011403507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5011403503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4127403 + ... + 4128616.

It is an arithmetic number, because the mean of its divisors is an integer number (1254915040).

Almost surely, 2^5011403533 is an apocalyptic number.

It is an amenable number.

5011403533 is a deficient number, since it is larger than the sum of its proper divisors (8256627).

5011403533 is an equidigital number, since it uses as much as digits as its factorization.

5011403533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8256626.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 5011403533 is about 70791.2673498646. The cubic root of 5011403533 is about 1711.2749441084.

Adding to 5011403533 its reverse (3353041105), we get a palindrome (8364444638).

The spelling of 5011403533 in words is "five billion, eleven million, four hundred three thousand, five hundred thirty-three".