Base | Representation |
---|---|
bin | 100100011101101010110… |
… | …1100110100011110001111 |
3 | 122202002121020200122110212 |
4 | 1020323111230310132033 |
5 | 1124102041343212112 |
6 | 14354131553153035 |
7 | 1025033032015046 |
oct | 110732554643617 |
9 | 18662536618425 |
10 | 5011517163407 |
11 | 1662410874927 |
12 | 68b322b5b77b |
13 | 2a47791a2c61 |
14 | 1347b71d955d |
15 | 8a5638b9522 |
hex | 48ed5b3478f |
5011517163407 has 2 divisors, whose sum is σ = 5011517163408. Its totient is φ = 5011517163406.
The previous prime is 5011517163397. The next prime is 5011517163413. The reversal of 5011517163407 is 7043617151105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5011517163407 - 28 = 5011517163151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5011517163487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505758581703 + 2505758581704.
It is an arithmetic number, because the mean of its divisors is an integer number (2505758581704).
Almost surely, 25011517163407 is an apocalyptic number.
5011517163407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5011517163407 is an equidigital number, since it uses as much as digits as its factorization.
5011517163407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 88200, while the sum is 41.
The spelling of 5011517163407 in words is "five trillion, eleven billion, five hundred seventeen million, one hundred sixty-three thousand, four hundred seven".
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