Base | Representation |
---|---|
bin | 1001010101011011… |
… | …00011011011101111 |
3 | 110221021010012220102 |
4 | 10222231203123233 |
5 | 40230424130413 |
6 | 2145142541315 |
7 | 235122326504 |
oct | 45255433357 |
9 | 13837105812 |
10 | 5011551983 |
11 | 21419881a9 |
12 | b7a43783b |
13 | 61b374999 |
14 | 35782b4ab |
15 | 1e4e89458 |
hex | 12ab636ef |
5011551983 has 2 divisors, whose sum is σ = 5011551984. Its totient is φ = 5011551982.
The previous prime is 5011551971. The next prime is 5011552019. The reversal of 5011551983 is 3891551105.
5011551983 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5011551983 is a prime.
It is a super-2 number, since 2×50115519832 = 50231306556622464578, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5011551383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505775991 + 2505775992.
It is an arithmetic number, because the mean of its divisors is an integer number (2505775992).
Almost surely, 25011551983 is an apocalyptic number.
5011551983 is a deficient number, since it is larger than the sum of its proper divisors (1).
5011551983 is an equidigital number, since it uses as much as digits as its factorization.
5011551983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 38.
The square root of 5011551983 is about 70792.3158471313. The cubic root of 5011551983 is about 1711.2918413213.
The spelling of 5011551983 in words is "five billion, eleven million, five hundred fifty-one thousand, nine hundred eighty-three".
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