Base | Representation |
---|---|
bin | 101110101011001010… |
… | …001011001101111101 |
3 | 11210100200111022221111 |
4 | 232223022023031331 |
5 | 1310114222232311 |
6 | 35004552202021 |
7 | 3422632525012 |
oct | 565312131575 |
9 | 153320438844 |
10 | 50116211581 |
11 | 1a288327587 |
12 | 9867999311 |
13 | 4958b6b487 |
14 | 25d5d41709 |
15 | 1484b9cd21 |
hex | bab28b37d |
50116211581 has 2 divisors, whose sum is σ = 50116211582. Its totient is φ = 50116211580.
The previous prime is 50116211569. The next prime is 50116211617. The reversal of 50116211581 is 18511261105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50115985956 + 225625 = 223866^2 + 475^2 .
It is a cyclic number.
It is not a de Polignac number, because 50116211581 - 25 = 50116211549 is a prime.
It is a super-2 number, since 2×501162115812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50116211501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25058105790 + 25058105791.
It is an arithmetic number, because the mean of its divisors is an integer number (25058105791).
Almost surely, 250116211581 is an apocalyptic number.
It is an amenable number.
50116211581 is a deficient number, since it is larger than the sum of its proper divisors (1).
50116211581 is an equidigital number, since it uses as much as digits as its factorization.
50116211581 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 31.
Adding to 50116211581 its reverse (18511261105), we get a palindrome (68627472686).
The spelling of 50116211581 in words is "fifty billion, one hundred sixteen million, two hundred eleven thousand, five hundred eighty-one".
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