Base | Representation |
---|---|
bin | 100100011101111100010… |
… | …0011111010100000111111 |
3 | 122202011010000020000120020 |
4 | 1020323320203322200333 |
5 | 1124104241110001143 |
6 | 14354310005023223 |
7 | 1025053363221444 |
oct | 110737043724077 |
9 | 18664100200506 |
10 | 5012102031423 |
11 | 1662690a27923 |
12 | 68b4669b4b13 |
13 | 2a48404010c6 |
14 | 134830b639cb |
15 | 8a599de8883 |
hex | 48ef88fa83f |
5012102031423 has 4 divisors (see below), whose sum is σ = 6682802708568. Its totient is φ = 3341401354280.
The previous prime is 5012102031407. The next prime is 5012102031427. The reversal of 5012102031423 is 3241302012105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5012102031423 - 24 = 5012102031407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5012102031393 and 5012102031402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5012102031427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 835350338568 + ... + 835350338573.
It is an arithmetic number, because the mean of its divisors is an integer number (1670700677142).
Almost surely, 25012102031423 is an apocalyptic number.
5012102031423 is a deficient number, since it is larger than the sum of its proper divisors (1670700677145).
5012102031423 is a wasteful number, since it uses less digits than its factorization.
5012102031423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1670700677144.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 5012102031423 its reverse (3241302012105), we get a palindrome (8253404043528).
The spelling of 5012102031423 in words is "five trillion, twelve billion, one hundred two million, thirty-one thousand, four hundred twenty-three".
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