Base | Representation |
---|---|
bin | 101110101100000111… |
… | …101101011100110101 |
3 | 11210101210211212111221 |
4 | 232230013231130311 |
5 | 1310132334430311 |
6 | 35010330030341 |
7 | 3423216611116 |
oct | 565407553465 |
9 | 153353755457 |
10 | 50132342581 |
11 | 1a296444a92 |
12 | 98712783b1 |
13 | 495c2c8849 |
14 | 25d814020d |
15 | 14862d7671 |
hex | bac1ed735 |
50132342581 has 2 divisors, whose sum is σ = 50132342582. Its totient is φ = 50132342580.
The previous prime is 50132342569. The next prime is 50132342639. The reversal of 50132342581 is 18524323105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38372892100 + 11759450481 = 195890^2 + 108441^2 .
It is a cyclic number.
It is not a de Polignac number, because 50132342581 - 27 = 50132342453 is a prime.
It is a super-2 number, since 2×501323425812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50132349581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25066171290 + 25066171291.
It is an arithmetic number, because the mean of its divisors is an integer number (25066171291).
Almost surely, 250132342581 is an apocalyptic number.
It is an amenable number.
50132342581 is a deficient number, since it is larger than the sum of its proper divisors (1).
50132342581 is an equidigital number, since it uses as much as digits as its factorization.
50132342581 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 50132342581 its reverse (18524323105), we get a palindrome (68656665686).
The spelling of 50132342581 in words is "fifty billion, one hundred thirty-two million, three hundred forty-two thousand, five hundred eighty-one".
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