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5013302041 = 11455754731
BaseRepresentation
bin1001010101101000…
…01110101100011001
3110221101102010112101
410222310032230121
540231401131131
62145244243401
7235143235636
oct45264165431
913841363471
105013302041
112142973030
12b7ab40561
1361b838417
14357b6518d
151e51d2c61
hex12ad0eb19

5013302041 has 4 divisors (see below), whose sum is σ = 5469056784. Its totient is φ = 4557547300.

The previous prime is 5013302033. The next prime is 5013302071. The reversal of 5013302041 is 1402033105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5013302041 - 23 = 5013302033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5013302071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227877355 + ... + 227877376.

It is an arithmetic number, because the mean of its divisors is an integer number (1367264196).

Almost surely, 25013302041 is an apocalyptic number.

It is an amenable number.

5013302041 is a deficient number, since it is larger than the sum of its proper divisors (455754743).

5013302041 is a wasteful number, since it uses less digits than its factorization.

5013302041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 455754742.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 5013302041 is about 70804.6752764251. The cubic root of 5013302041 is about 1711.4910152465.

Adding to 5013302041 its reverse (1402033105), we get a palindrome (6415335146).

The spelling of 5013302041 in words is "five billion, thirteen million, three hundred two thousand, forty-one".

Divisors: 1 11 455754731 5013302041