Base | Representation |
---|---|
bin | 101110101100001011… |
… | …001000101001010011 |
3 | 11210101212112111002121 |
4 | 232230023020221103 |
5 | 1310133102143103 |
6 | 35010401155111 |
7 | 3423230340511 |
oct | 565413105123 |
9 | 153355474077 |
10 | 50133240403 |
11 | 1a2969a8594 |
12 | 987162ba97 |
13 | 495c5513bc |
14 | 25d82d54b1 |
15 | 14864136bd |
hex | bac2c8a53 |
50133240403 has 2 divisors, whose sum is σ = 50133240404. Its totient is φ = 50133240402.
The previous prime is 50133240371. The next prime is 50133240413. The reversal of 50133240403 is 30404233105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50133240403 - 25 = 50133240371 is a prime.
It is not a weakly prime, because it can be changed into another prime (50133240413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25066620201 + 25066620202.
It is an arithmetic number, because the mean of its divisors is an integer number (25066620202).
Almost surely, 250133240403 is an apocalyptic number.
50133240403 is a deficient number, since it is larger than the sum of its proper divisors (1).
50133240403 is an equidigital number, since it uses as much as digits as its factorization.
50133240403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 50133240403 its reverse (30404233105), we get a palindrome (80537473508).
The spelling of 50133240403 in words is "fifty billion, one hundred thirty-three million, two hundred forty thousand, four hundred three".
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